Sodium Lauryl Sulfate
Sulfuric acid monododecyl ester sodium salt.
Sodium monododecyl sulfate
Sodium Lauryl Sulfate is a mixture of sodium alkyl sulfates consisting chiefly of sodium lauryl sulfate [CH3(CH2)10CH2OSO3Na]. The combined content of sodium chloride and sodium sulfate is not more than 8.0 percent. It contains not less than 85.0% of sodium alkyl sulfates calculated as C12H25NaO4S.
Identification—
A: Place 2.5 g in a silica or platinum crucible, and add 2 mL of 10 N sulfuric acid. Heat on a water bath, then cautiously raise the temperature progressively over an open flame. Ignite, preferably in a muffle furnace, at 600 ± 25 . Continue heating until all black particles have disappeared. Cool, add a few drops of 2 N sulfuric acid, and heat and ignite as above. Add a few drops of 2 M ammonium carbonate, evaporate to dryness, and ignite as above. Cool, dissolve the residue in 50 mL of water, and mix.
To a 2 mL portion of this solution, add 4 mL of Potassium pyroantimonate solution. If necessary, rub the inside of the test tube with a glass rod. A white, crystalline precipitate is formed.
B: Prepare a solution (1 in 10) after acidification with hydrochloric acid and boiling for 20 minutes. No precipitate is formed. Add barium chloride solution; a white precipitate is produced.
C: Dissolve 0.1 g in 10 mL of water and shake. A copious foam is formed.
D: To 0.1 mL of the solution prepared for identification C, add 0.1 mL of a 1 g/L solution of methylene blue and 2 mL of dilute sulfuric acid. Add 2 mL of methylene chloride and shake. An intense blue color develops in the methylene chloride layer.
Alkalinity—Dissolve 1.0 g in 100 mL of water, add phenol red solution, and titrate with 0.10 N hydrochloric acid: not more than 0.5 mL is required for neutralisation.
Sodium chloride—Dissolve about 5 g, accurately weighed, in about 50 mL of water.
Neutralize the solution with dilute nitric acid, if necessary, add exactly 5.0 mL of 0.1 N Sodium Chloride and titrate with 0.1 N Silver Nitrate (indicator: 2 drops of fluorescein sodium solution) to the first appearance of turbidity. Perform a blank determination, and make any necessary correction. Each mL of 0.1 N Silver Nitrate = 5.844 mg of NaCl.